So you replaced the Hamiltonian [...] by its normal-ordered formSo that's what I was doing. Though actually I had already noted dangerous signs of normality in my thought processes, when trying to prove the Baker-Campbell-Hausdorff formula. After all, if we set A = za*/sq2,
Speaking of Baker-Campbell-Hausdorff: is there a slick proof of their formula, or does one just have to fight it out with Taylor series? I did notice one thing: we can prove pretty easily that eA+Be-Be-A is a number (i.e., a multiple of the identity operator) in the case at hand. First we show that this product of exponentials commutes with A, using the ``derivative = bracket'' trick:
I omit the details (which are not messy), but it's essential here that
[A,B] commutes with A and B. Next we appeal
to Schur's lemma. The irreducibility hypothesis is satisfied since {|0>,
A|0>, ..., An |0>,...} span the whole Hilbert
space.