It has been suggested that the regular icosahedron, not being found in nature, is the first example of a geometrical object that is the free creation of human thought. Regardless of the truth of this, it is interesting to try to track down the origin of the icosahedron. A scholium in Book XIII of Euclid's "Elements" speaks of "the five so-called Platonic figures which, however, do not belong to Plato, three of the five being due to the Pythagoreans, namely the cube, the pyramid, and the dodecahedron, while the octahedron and the icosahedron are due to Theaetetus." More recently, Atiyah and Sutcliffe have claimed that a regular icosahedron appears among a collection of stone balls in the Ashmolean Museum - balls that were unearthed in Scotland and may date back to 2000 BC. However, Lieven le Bruyn has argued that these authors are the victims of a hoax. We examine the evidence with a critical eye.Click here to see the slides of this talk: Also try these related talks: Also read this more detailed account, taken from "week283" of This Week's Finds:

The dodecahedron and icosahedron are the most exotic of the Platonic solids, because they have 5-fold rotational symmetry - a possibility that only exists for regular polytopes in 2, 3 or 4 dimensions. The dodecahedron and icosahedron have the same symmetry group, because they are Poincaré duals: the vertices of one correspond to faces of the other. But the icosahedron was probably discovered later. As Benno Artmann wrote:

The original knowledge of the dodecahedron may have come from crystals of pyrite, but in contrast the icosahedron is a pure mathematical creation.... It is the first realization of an entity that existed before only in abstract thought. (Well, apart from the statues of gods!)I'm not sure it's really anything close to the first "realization of an entity that existed before only in abstract thought". But it may have been the first "exceptional" object in mathematics - roughtly speaking, an entity that doesn't fit into any easy pattern, which is discovered as part of proving a classification theorem!

Other exceptional objects include the simple Lie group E

_{8}, and the finite simple group M_{12}. Intriguingly, many of these exceptional objects" are related. For example, the icosahedron can be used to construct both E_{8}and M_{12}. But the first interesting classification theorem was the classification of regular polyhedra: convex polyhedra with equilateral polygons as faces, and the same number of faces meeting at each vertex. This theorem appears almost at the end of the last book of Euclid's Elements - Book XIII. It shows that the only possibilities are the Platonic solids: the tetrahedron, the cube, the octahedron, the dodecahedron and the icosahedron. And according to traditional wisdom, the results in this book were proved by Theatetus, who also discovered the icosahedron!Indeed, Artmann cites an "an ancient note written in the margins of the manuscript" of Book XIII, which says:

In this book, the 13th, are constructed the five so-called Platonic figures which, however, do not belong to Plato, three of the five being due to the Pythagoreans, namely the cube, the pyramid, and the dodecahedron, while the octahedron and the icosahedron are due to Theaetetus.You may know Theaetetus through Plato's dialog of the same name, where he's described as a mathematical genius. He's also mentioned in Plato's dialogue called the Sophist. In the Republic, written around 380 BC, Plato complained that not enough is known about solid geometry:

... and for two reasons: in the first place, no government places value on it; this leads to a lack of energy in the pursuit of it, and it is difficult. In the second place, students cannot learn it unless they have a teacher. But then a teacher can hardly be found....Theaetetus seems to have filled the gap: he worked on solid geometry between 380 and 370 BC, perhaps inspired by Plato's interest in the subject. He died from battle wounds and dysentery in 369 after Athens fought a battle with Corinth.

But how certain are we that Theatetus discovered - or at least studied - the icosahedron? The only hard evidence seems to be this "ancient note" in the margins of the Elements. But who wrote it, and when?

First of all, if you hope to see an ancient manuscript by Euclid with a scribbled note in the margin, prepare to be disappointed! All we have are copies of copies of copies. The oldest remaining fragments of the Elements date to centuries after Euclid's death: some from a library in Herculaneum roasted by the eruption of Mount Vesuvius in 79 AD, a couple from the Fayum region near the Nile, and some from a garbage dump in the Egyptian town of Oxyrhynchus.

There are various lines of copies of Euclid's Elements. Comparing these to guess the contents of the

originalElements is a difficult and fascinating task. Unfortunately, in the fourth century AD, the Greek mathematician Theon of Alexandria - Hypatia's dad - made a copy that became extremely popular. So popular, in fact, that for many centuries European scholars knew no line of copies that hadn't passed through Theon! And Theon wasn't a faithful copyist: he added extra propositions, lengthened some proofs, and omitted a few things too. It seems he wanted to standardize the language and make it easier to follow. This may have helped people trying to learn geometry - but certainly not scholars trying to understand Euclid.In 1808, Francois Peyrard made a marvelous discovery. He found that the Vatican library had a copy of Euclid's Elements that hadn't descended through Theon!

This copy is now called "P". It dates back to about 850 AD. I would love to know how Peyrard got his hands on it. One imagines him rooting around in a dusty basement and opening a trunk... but it seems that Napoleon somehow took this manuscript from the Vatican to Paris.

In the 1880s, the great Danish scholar Johan Heiberg used "P" together with various "Theonine" copies of the Elements to prepare what's still considered the definitive Greek edition of this book. The all-important English translation by Thomas Heath is based on this. As far as I can tell, "P" is the only known non-Theonine copy of Euclid except for the fragments I mentioned. Heath also used these fragments to prepare his translation.

This is just a quick overview of a complicated detective story. As always, the fractal texture of history reveals more complexity the more closely you look.

Anyway, Heath thinks that Geminus of Rhodes wrote the "ancient note" in the Elements crediting Theatetus. I'm not sure why Heath thinks this, but Geminus of Rhodes was a Greek astronomer and mathematician who worked during the 1st century BC.

In his charming article "The discovery of the regular solids", William Waterhouse writes:

Once upon a time there was no problem in the history of the regular solids. According to Proclus, the discoveries of Pythagoras include "the construction of the cosmic solids," and early historians could only assume that the subject sprang full-grown from his head. But a better-developed picture of the growth of Greek geometry made such an early date seem questionable, and evidence was uncovered suggesting a different attribution. A thorough study of the testimony was made by E. Sachs, and her conclusion is now generally accepted: the attribution to Pythagoras is a later misunderstanding and/or invention.The history of the regular solids thus rests almost entirely on a scholium to Euclid which reads as follows:

"In this book, the 13th, are constructed the 5 figures called Platonic, which however do not belong to Plato. Three of these 5 figures, the cube, pyramid, and dodecahedron, belong to the Pythagoreans; while the octahedron and icosahedron belong to Theaetetus."

Theaetetus lived c. 415-369 B.C., so this version gives a moderately late date; and it has the considerable advantage of seeming unlikely. That is, the details in the scholium are not the sort of history one would naively conjecture, and hence it is probably not one of the stories invented in late antiquity. As van der Waerden says, the scholium is now widely accepted "precisely because [it] directly contradicts the tradition which used to ascribe to Pythagoras anything that came along."

But probability arguments can cut both ways, and those scholars who hesitate to accept the scholium do so primarily because it seems too unlikely. There have been two main sticking places: first, the earliness of the dodecahedron in comparison with the icosahedron; and second, the surprising lateness of the octahedron. The first objection, however, has been fairly well disposed of. The mineral pyrite (FeS

_{2}) crystallizes most often in cubes and almost-regular dodecahedra; it is quite widespread, being the most common sulphide, and outstanding crystals are found at a number of spots in Italy. Moreover it regularly occurs mixed with the sulphide ores, and underlying the oxidized ores, of copper; these deposits have been worked since earliest antiquity. Thus natural dodecahedra were conspicuous, and in fact they did attract attention: artificial dodecahedra have been found in Italy dating from before 500 BC. Icosahedral crystals, in contrast, are much less common. Hence there is no real difficulty in supposing that early Pythagorean geometers in Italy were familiar with dodecahedra but had not yet thought of the icosahedron.Indeed, while I've heard that iron pyrite forms "pseudoicosahedra":

I've never seen one, while the "pyritohedra" resembling regular dodecahedra are pretty common:

The puzzle of why the octahedron showed up so late seems to have this answer: it was known earlier, but it was no big deal until the concept of regular polyhedron was discovered! As Waterhouse says, the discovery of the octahedron would be like the discovery of the 4rd perfect number. Only the surrounding conceptual framework makes the discovery meaningful.

So far, so good. But maybe the Greeks were not the first to discover the icosahedron! In 2003, the mathematicians Michael Atiyah and Paul Sutcliffe wrote:

Although they are termed Platonic solids there is convincing evidence that they were known to the Neolithic people of Scotland at least a thousand years before Plato, as demonstrated by the stone models pictured in Fig. 1 which date from this period and are kept in the Ashmolean Museum in Oxford.

Figure 1. Stone models of the cube, tetrahedron, dodecahedron, icosahedron and octahedron.

They date from about 2000 BC and are kept in the Ashmolean Museum in Oxford.Various people including John McKay and myself spread this story without examining it very critically. I did read Dorothy Marshall's excellent paper "Carved stone balls", which catalogues 387 carved stone balls found in Scotland, dating from the Late Neolithic to Early Bronze Age. It has pictures showing a wide variety of interesting geometric patterns carved on them, and maps showing where people have found balls with various numbers of bumps on them. But it doesn't say anything about Platonic solids.

Maps by Dorothy Marshall.

Left: balls with 3 or 4 knobs. Right: balls with 6 knobs.In March of 2009, Lieven le Bruyn posted a skeptical investigation of Atiyah and Sutcliffe's claim. For starters, he looked hard at the photo in their paper:

... where's the icosahedron? The fourth ball sure looks like one but only because someone added ribbons, connecting the centers of the different knobs. If this ribbon-figure is an icosahedron, the ball itself should be another dodecahedron and the ribbons illustrate the fact that icosa- and dodecahedron are dual polyhedra. Similarly for the last ball, if the ribbon-figure is an octahedron, the ball itself should be another cube, having exactly 6 knobs. Who did adorn these artifacts with ribbons, thereby multiplying the number of "found" regular solids by two (the tetrahedron is self-dual)?

Who put on the ribbons?Lieven le Bruyn traced back the photo to Robert Lawlor's 1982 book Sacred Geometry. In this book, Lawlor wrote:

The five regular polyhedra or Platonic solids were known and worked with well before Plato's time. Keith Critchlow in his book Time Stands Still presents convincing evidence that they were known to the Neolithic peoples of Britain at least 1000 years before Plato. This is founded on the existence of a number of spherical stones kept in the Ashmolean Museum at Oxford. Of a size one can carry in the hand, these stones were carved into the precise geometric spherical versions of the cube, tetrahedron, octahedron, icosahedron and dodecahedron, as well as some additional compound and semi-regular solids...

But is this really true?Le Bruyn discovered that the Ashmolean owns only 5 Scottish stone balls - and their webpage shows a photo of them, which looks quite different than the photo in Lawlor's book!They have no ribbons on them. More importantly, they're different shapes! The Ashmolean lists their 5 balls as having 7, 6, 6, 4 and 14 knobs, respectively - nothing like an icosahedron.

And here is where I did a little research of my own. The library at UC Riverside has a copy of Keith Critchlow's 1979 book Time Stands Still. In this book, we see the same photo of stones with ribbons that appears in Lawlor's book - the photo that Atiyah and Suttcliffe use. In Critchlow's book, these stones are called "a full set of Neolithic 'Platonic solids'". He says they were photographed by one Graham Challifour - but he gives no information as to where they came from!

And Critchlow explicitly denies that the Ashmolean has an icosahedral stone! He writes:

... the author has, during the day, handled five of these remarkable objects in the Ashmolean museum.... I was rapt in admiration as I turned over these remarkable stone objects when another was handed to me which I took to be an icosahedron.... On careful scrutiny, after establishing apparent fivefold symmetry on a number of the axes, a count-up of the projections revealed 14! So it was not an icosahedron.It seems the myth of Scottish balls shaped like Platonic solids gradually grew with each telling. Could there be any truth to it? Dorothy Marshall records Scottish stone balls with various numbers of knobs, from 3 to 135 - but just two with 20, one at the National Museum in Edinburgh, and one at the Kelvingrove Art Gallery and Museum in Glasgow. Do these look like icosahedra? I'd like to know. But even if they do, should we credit Scots with "discovering the icosahedron"? Perhaps not.

So, it seems the ball is in Theaetetus' court.

Here are some references:

The quote from Benno Artmann appeared in a copy of the AMS Bulletin where the cover illustrates a construction of the icosahedron:

5) Benno Artmann, About the cover: the mathematical conquest of the third dimension, Bulletin of the AMS, 43 (2006), 231-235. Also available at http://www.ams.org/bull/2006-43-02/S0273-0979-06-01111-6/

For more, try this wonderfully entertaining book:

6) Benno Artmann, Euclid - The Creation of Mathematics, Springer, New York, 2nd ed., 2001. (The material on the icosahedron is not in the first edition.)

It's not a scholarly tome: instead, it's a fun and intelligent introduction to Euclid's Elements with lots of interesting digressions. A great book for anyone interested in math!

I should also get ahold of this someday:

7) Benno Artmann, Antike Darstellungen des Ikosaeders, Mitt. DMV 13 (2005), 45-50.

Heath's translation of and commentary on Euclid's Elements is available online thanks to the Perseus Project. The scholium crediting Theatetus for the octahedron and icosahedron is discussed here:

8) Euclid, Elements, trans. Thomas L. Heath, Book XIII, Historical Note, p. 438. Also available at http://old.perseus.tufts.edu/cgi-bin/ptext?doc=Perseus%3Atext%3A1999.01.0086&query=head%3D%23566

while the textual history of the Elements is discussed here:

9) Euclid, Elements, trans. Thomas L. Heath, Chapter 5: The Text, p. 46. Also available at http://old.perseus.tufts.edu/cgi-bin/ptext?lookup=Euc.+5

Anyone interested in Greek mathematics also needs these books by Heath, now available cheap from Dover:

10) Thomas L. Heath, A History of Greek Mathematics. Vol. 1: From Thales to Euclid. Vol. 2: From Aristarchus to Diophantus. Dover Publications, 1981.

The long quote by Waterhouse comes from here:

11) William C. Waterhouse, The discovery of the regular solids, Arch. Hist. Exact Sci. 9 (1972-1973), 212-221.

I haven't yet gotten my hold on this "thorough study" mentioned by Waterhouse - but I will soon:

12) Eva Sachs, Die funf platonischen Koerper, zur Geschichte der Mathematik und der Elementenlehre Platons und der Pythagoreer, Berlin, Weidmann, 1917.

I also want to find this discussion of how Peyrard got ahold of the non-Theonine copy of Euclid's Elements:

13) N. M. Swerlow, The Recovery of the exact sciences of antiquity: mathematics, astronomy, geography, in Rome Reborn: The Vatican Library and Renaissance Culture, ed. Grafton, 1993.

Here is Atiyah and Sutcliffe's paper claiming that the Ashmolean has Scottish stone balls shaped like Platonic solids:

14) Michael Atiyah and Paul Sutcliffe, Polyhedra in physics, chemistry and geometry, available as arXiv:math-ph/0303071.

Here is le Bruyn's critical examination of that claim:

15) Lieven le Bruyn, The Scottish solids hoax, March 25, 2009, http://www.neverendingbooks.org/index.php/the-scottish-solids-hoax.html

Here are the books by Critchlow and Lawlor -speculative books from the "sacred geometry" tradition:

16) Keith Critchlow, Time Stands Still, Gordon Fraser, London, 1979.

17) Robert Lawlor, Sacred Geometry: Philosophy and Practice, Thames and Hudson, London, 1982. Available at http://www.scribd.com/doc/13155707/robert-lawlor-sacred-geometry-philosophy-and-practice-1982

Here's the Ashmolean website:

18) British Archaeology at the Ashmolean Museum, Highlights of the British collections: stone balls, http://ashweb2.ashmus.ox.ac.uk/ash/britarch/highlights/stone-balls.html

and here's Dorothy Marshall's paper on stone balls:

19) Dorothy N. Marshall, Carved stone balls, Proc. Soc. Antiq. Scotland, 108 (1976/77), 40-72. Available at http://www.tarbat-discovery.co.uk/Learning%20Files/Carved%20stone%20balls.pdf

Finally, a bit of math.

In the process of researching my talk, I learned a lot about Euclid's Elements, where the construction of the icosahedron - supposedly due to Theaetetus - is described. This construction is Proposition XIII.16, in the final book of the Elements, which is largely about the Platonic solids. This book also has some fascinating results about the golden ratio and polygons with 5-fold symmetry!

The coolest one is Proposition XIII.10. It goes like this.

Take a circle and inscribe a regular pentagon, a regular hexagon, and a regular decagon. Take the edges of these shapes, and use them as the sides of a triangle. Then this is a right triangle!

In other words, if

P

is the side of the pentagon,

H

is the side of the hexagon, and

D

is the side of the decagon, then

P

^{2}= H^{2}+ D^{2}We can prove this using algebra - but Euclid gave a much cooler proof, which actually find this right triangle hiding inside an icosahedron.

First let's give a completely uninspired algebraic proof.

Start with a unit circle. If we inscribe a regular hexagon in it, then obviously

H = 1

So we just need to compute P and D. If we think of the unit circle as living in the complex plane, then the solutions of

z

^{5}= 1are the corners of a regular pentagon. So let's solve this equation. We've got

0 = z

^{5}- 1 = (z - 1)(z^{4}+ z^{3}+ z^{2}+ z + 1)so ignoring the dull solution z = 1, we must solve

z

^{4}+ z^{3}+ z^{2}+ z + 1 = 0This says that the center of mass of the pentagon's corners lies right in the middle of the pentagon.

Now, quartic equations can always be solved using radicals, but it's a lot of work. Luckily, we can solve this one by repeatedly using the quadratic equation! And that's why the Greeks could construct the regular pentagon using a ruler and compass.

The trick is to rewrite our equation like this:

z

^{2}+ z + 1 + z^{-1}+ z^{-2}= 0and then like this:

(z + z

^{-1})^{2}+ (z + z^{-1}) - 1 = 0Now it's a quadratic equation in a new variable. So while I said this proof would be uninspired, it did require a tiny glimmer of inspiration. But that's all! Let's write

z + z

^{-1}= xso our equation becomes

x

^{2}+ x - 1 = 0Solving this, we get two solutions. The one I like is the golden ratio:

x = φ = (-1 + √5)/2 ~ 0.6180339...

Next we need to solve

z + z

^{-1}= φThis is another quadratic equation:

z

^{2}- φ z + 1 = 0with two conjugate solutions, one being

z = (φ + (φ

^{2}- 4)^{½})/2I've sneakily chosen the solution that's my favorite 5th root of unity:

z = exp(2πi/5) = cos(2π/5) + i sin(2π/5)

So, we're getting

cos(2π/5) = φ/2

A fact we should have learned in high school, but probably never did.

Now we're ready to compute P, the length of the side of a pentagon inscribed in the unit circle:

P

^{2}= |1 - z|^{2}

= (1 - cos(2π/5))^{2}+ (sin(2π/5))^{2}

= 2 - 2 cos(2π/5)

= 2 - φNext let's compute D, the length of the side of a decagon inscribed in the unit circle! We can mimic the last stage of the above calculation, but with an angle half as big:

D

^{2}= 2 - 2 cos(π/5)To go further, we can use a half-angle formula:

cos(π/5) = ((1 + cos(2π/5))/2)

^{½}

= (½ + φ/4)^{½}This gives

D

^{2}= 2 - (2 + φ)^{½}But we can simplify this a bit more. As any lover of the golden ratio should know,

2 + φ = 2.6180339...

is the square of

1 + φ = 1.6180339...

So we really have

D

^{2}= 1 - φOkay. Your eyes have glazed over by now - unless you've secretly been waiting all along for This Week's Finds to cover high-school algebra and trigonometry. But we're done. We see that

P

^{2}= H^{2}+ D^{2}simply says

2 - φ = 1 + (1 - φ)

That wasn't so bad, but imagine discovering it and proving it using axiomatic geometry back around 300 BC! How did they do it?

For this, let's turn to

20) Ian Mueller, Philosophy of Mathematics and Deductive Structure in Euclid's Elements, MIT Press, Cambridge Massachusetts, 1981.

This is reputed to be be the most thorough investigation of the logical structure of Euclid's Elements! And starting on page 257 he discusses how people could have discovered P

^{2}= H^{2}+ D^{2}by staring at an icosahedron!This should not be too surprising. After all, there are pentagons, hexagons and decagons visible in the icosahedron. But I was stuck until I cheated and read Mueller's explanation.

If you hold an icosahedron so that one vertex is on top and one is on bottom, you'll see that its vertices are arranged in 4 horizontal layers. From top to bottom, these are:

- 1 vertex on top
- 5 vertices forming a pentagon: the "upper pentagon"
- 5 vertices forming a pentagon: the "lower pentagon"
- 1 vertex on bottom

Pick a vertex from the upper pentagon: call this A. Pick a vertex as close as possible from the lower pentagon: call this B. A is not directly above B. Drop a vertical line down from A until it hits the horizontal plane on which B lies. Call the resulting point C.

If you think about this, or better yet draw it, you'll see that ABC is a right triangle. And if we apply the Pythagorean theorem to this triangle we'll get the equation

P

^{2}= H^{2}+ D^{2}To see this, we only need to check that:

- the length AB equals the edge of a pentagon inscribed in a circle;

- the length AC equals the edge of a hexagon inscribed in a circle;

- the length BC equals the edge of a decagon inscribed in a circle.
Different circles, but of the same radius! What's this radius? Take all 5 vertices of the "upper pentagon". These lie on a circle, and this circle has the right radius.

Using this idea, it's easy to see that the length AB equals the edge of a pentagon inscribed in a circle. It's also easy to see that BC equals the edge of a decagon inscribed in a circle of the same radius. The hard part, at least for me, is seeing that AC equals the edge of a hexagon inscribed in a circle of the same radius... or in other words, the radius of that circle! (The hexagon seems to be a red herring.)

To prove this, we need a wonderful fact: the distance between the "upper pentagon" and the "lower pentagon" equals the radius of the circle containing the vertices of the upper pentagon!

Can you prove this?

I just found a very beautiful proof. I could explain it easily with lots of pictures, but I'm too lazy to draw them electronically. I don't feel too guilty about this, though: I've given enough clues for you to figure everything out and draw the pictures yourself. It's lots of fun. And if you draw nice electronic pictures, I'd love to include them here and credit you!

Okay, okay... I'll give you one more hint. Consider the "top" vertex of the icosahedron and the 5 vertices forming the "upper pentagon". Let

Abe any vertex on the upper pentagon, and letBbe the top vertex. Drop a vertical line from the top vertex until it hits the plane of the upper pentagon; call the point where it hitsC. Prove that the triangleABCis congruent to the right triangle ABC. And using this, show the distance between the "upper pentagon" and the "lower pentagon" equals the radius of the circle containing the vertices of the upper pentagon!So, we also get:

- the length
ABequals the edge of a pentagon inscribed in a circle;

- the length
ACequals the edge of a hexagon inscribed in a circle;

- the length
BCequals the edge of a decagon inscribed in a circle.I thank Toby Bartels for help with some of this stuff.

Addendum:Kevin Buzzard explained some of the Galois theory behind why the pentagon can be constructed with ruler and compass - or in other words, why the quarticz

^{4}+ z^{3}+ z^{2}+ z + 1 = 0can be solved by solving first one quadratic and then another.

He wrote:

Now, quartic equations can always be solved using radicalsThat's because S_{4}is a solvable group, and all Galois groups of quartics will live in S_{4}(and will usually be S_{4})...Luckily, we can solve this one by repeatedly using the quadratic equation!("this one" being z

^{4}+ z^{3}+ z^{2}+ z + 1 = 0.)...and

that'sbecause the Galois group of thatspecificirreducible polynomial is "only" cyclic of order 4. The splitting field is Q(ζ_{5}), which is a cyclotomic field, so has Galois group (Z/5Z)*. No Z/3Z factors so no messing around with cube roots, for example...

So while I said this proof would be uninspired, it did require a tiny glimmer of inspiration.With this observation above, I'm trying to convince you that the proof really

iscompletely uninspired To solve the quartic by solving two quadratics, you need to locate the degree 2 subfield of Q(z) (z=ζ_{5}) and aim towards it (because it's your route to the solution). This subfield is clearly the real numbers in Q(z), and the real numbers in Q(z) contains z+z*=z+z^{-1}. So that's sort of a completely conceptual explanation of why the trick works and why it's crucial to introduce z+z^{-1}.

© 2009 John Baez - except for images

email: baez@math.removethis.ucr.andthis.edu